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Spherical waves

We now consider spherically symmetric solutions to the wave equation


\begin{displaymath}
\nabla^2 \xi - \frac{1}{c_s^2 } \frac{\partial^2 \xi}{\partial
t^2} = 0 \,.
\end{displaymath} (15.40)

where $\xi(\vec{r},t)=\xi(r,t)$ depends only on the distance $r$ from the origin. It is now convenient to use the spherical polar coordinates instead of $(x,y,z)$, and the wave equation becomes
\begin{displaymath}
\frac{1}{r^2} \frac{\partial}{\partial r} \left( r^2
\frac{\...
... \frac{1}{c_s^2 } \frac{\partial^2 \xi}{\partial
t^2} = 0 \,.
\end{displaymath} (15.41)

Substituting $\xi(r,t)=u(r,t)/r$ we have
(15.42)

which gives us the wave equation in a single variable $r$,
\begin{displaymath}
\frac{\partial^2 u}{\partial r^2}
- \frac{1}{c_s^2 } \frac{\partial^2 u}{\partial
t^2} = 0 \,.
\end{displaymath} (15.43)

whose solutions are already known. Using these we have
\begin{displaymath}
\xi(r,t)=\frac{f_1(r+c t)}{r}+\frac{f_1(r-c t)}{r}
\end{displaymath} (15.44)

which is the most general spherical wave solution. The first part of the solution $f_1(r+c t)$ represents a spherical wave travelling towards the origin and the second part $f_1(r-c t)$ represents a wave travelling out from the origin as shown in the left and right panels of Figure 15.7 respectively. In both cases the amplitude varies as $1/r$ and the solution is singular at $r=0$.

Figure 15.7: Spherical waves


next up previous contents
Next: Standing Waves Up: Solving the wave equation Previous: Plane waves   Contents
Physics 1st Year 2009-01-06