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Linear polarization

In this situation where both dipoles receive the same signal, the two components are equal $ E_y = E_z $ and
\begin{displaymath}
\vec E ( x, t) = E ( \widehat j + \widehat k ) \cos ( \omega t - k x )
\end{displaymath} (8.2)

If we plot the time evolution of the electric field at a fixed position (Figure 19.2) we see that it oscillates up and down along a direction which is at $45^\circ $ to the $y$ and $z$ axis.

Figure 8.2: Linear Polarization
\begin{figure}
\epsfig{file=chapt8//f2.eps,width=5.5in,height=2.0in}
\end{figure}

The point to note is that it is possible to change the relative amplitudes of $E_y $ and $E_z $ by changing the currents in the oscillators. The resultant electric field is

(8.3)

The resultant electric field vector has magnitude $ E = \sqrt{E_y^2 +
E^2_z }$ and it oscillates along a direction at an angle with respect to the $y$ axis (Figure 19.2).

Under no circumstance does the electric field have a component along the direction of the wave i.e along the $x$ axis. The electric field can be oriented along any direction in the $y-z$ plane. In the cases which we have considered until now, the electric field oscillates up and down a fixed direction in the $y-z$ plane . Such an electromagnetic wave is said to be linearly polarized.


next up previous contents
Next: Circular polarization Up: The vector nature of Previous: The vector nature of   Contents
Physics 1st Year 2009-01-06